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Quantitative Aptitude Practice Set For IBPS RRB / So Exam 2021

 Quantitative Aptitude Practice Set For IBPS RRB / So Exam 2021



Directions (1-5): Given bar graph shows the total number of passed students from six different colleges.



And given pie-chart shows the percentage distribution of number of passed students in different subjects from college E.



 

Q1. If number of passed boys in Maths from college B is equal to the sum of number of passed boys in Hindi and physics together from college E and the number of passed boys in Hindi & Physics together are 25% of total number of passed students in college E. Then find number of passed girls in Maths from college B is what percent of number of passed students in college B? (If passed girls in Maths from college B is 50% more than number of passed boys in same subject from the same college?
(a) 4.2%
(b) 3.6%
(c) 5.2%
(d) 4.8%
(e) 7.4%

Q2. If number of passed boys from college A are 300% more than number of passed students in English from college E and total number of passed girls from college A are 20% percent of total number of appeared students in the same college. Then find total number of appeared students in college A?
(a) 40,800
(b) 38,200
(c) 36,000
(d) 41,200
(e) 42,400

Q3. Ratio of number of failed boys to number of failed girls in Maths from college C is 3 : 2 and number of failed students in Maths from college C is 2/5th of number of passed students from college B. And number of passed boys in college C is 50% more than number of passed girls in the same college. Then number of failed girls in college C is what percent of total number of passed girls in the same college?
(a) 30%
(b) 25%
(c) 40%
(d) 45%
(e) 50%

Q4. If ratio of number of failed students from college A, B, C and D are 2 : 3 : 5 : 4. And number of failed students in English from college D is Quantitative Aptitude Quiz For RRB PO Mains 2021- 30th August_70.1 of total number of failed students from the same college. Then find average of number of failed students from college A, B & C? (given that failed number of student in English from college D is equal to number of passed student in History from college E)
(a) 3200
(b) 4400
(c) 5000
(d) 3000
(e) 4000

Q5. If total number of failed students in computer & English together from college C is 1200 which is 15% of total number of failed student from same college. And ratio of number of failed students from college C and college E is 4 : 5. Then find the ratio of total number of appeared student from college C to total number of appeared student from college E?
(a) 9 : 16
(b) 16 : 9
(c) 19 : 11
(d) 17 : 9
(e) 11 : 4

Directions (6-10): Study the following graph carefully and answer the question. The following bar graph shows the budget allocation (in crore) for education, sport and Health care from year 2018-22.

 


Q6. What percent is the average budget of sport during 2018 to 2022 than that of average budget of Education throughout all the years? (approximately)
(a) 84%
(b) 88%
(c) 87%
(d) 90%
(e) 94%

Q7. In 2022, budget allocated for sport for male to female are in the ratio of 3 : 2 and it proposed that budget allocated for males to be increased by 25% in 2023 compared to previous year for sport then, what is the percentage increase in sport budget allocation for 2023 with no change in sport budget allocated for female in 2023 as compared to previous year?
(a) 20%
(b) 18%
(c) 15%
(d) 12%
(e) 10%

Q8. Find the ratio between total budget allocated for Education from year 2018 to 2020 together to total budget allocated for Health care from year 2020 to 2022 together ?
(a) 17 : 29
(b) 18 : 29
(c) 21 : 29
(d) 27 : 29
(e) 17 : 27

Q9. If in 2019 budget allocated for only three sports i.e. Cricket, Badminton and Hockey in the ratio of 5 : 4 : 4 respectively and budget allocated for Education in 2022 for Urban and rural area in the ratio of 5 : 6 respectively. Then find budget allocated for Education for rural area in 2022 how much more than budget allocated for Cricket & Badminton together in 2019 ?
(a)30 cr
(b)35 cr
(c)40 cr
(d)45 cr
(e)25 cr

Q10.Find the sum of average of budget allocated for Health care throughout all the year 2018-22 and average of budget allocated for Education throughout all the year 2018-2022?
(a) 336
(b) 338
(c) 340
(d) 342
(e) 348


Solution:





 


Quantitative Aptitude Practice Set For IBPS RRB / So Exam 2021

 Quantitative Aptitude Practice Set For IBPS RRB / So Exam                                                       2021



Directions (1-15): What should come in place of question mark (?) in the following questions?

Q1. 323 × 15 + (?)² = 4989.
(a) 12
(b) 11
(c) 13
(d) 14
(e) 17

Q2. 5760 ÷ 45 × 15 =?
(a) 1850
(b) 1875
(c) 1920
(d) 1925
(e) 1970

Q3. 81% of 2300 – 34% of 550 = ?
(a) 1574
(b) 1676
(c) 1624
(d) 1596
(e) 1723

Q4. 25639 – 5252 – 3232 = ?
(a) 17254
(b) 16154
(c) 17155
(d) 16255
(e) 17815







Q6. 27% of 450 – ?% of 375 = 76.5
(a) 12
(b) 13
(c) 14
(d) 11
(e) 19

Q7. 311 × 17 = ? + 2482
(a) 2605
(b) 2715
(c) 2905
(d) 2805
(e) 2875









Q10. 1615 ÷ (50 × 0.85) = ?
(a) 35
(b) 34
(c) 38
(d) 37
(e) 28

Q11. 4.4 + 14.44 + 41.14 = ? – 14.41 – 1.4
(a) 74.21
(b) 75.79
(c) 76.19
(d) 78.79
(e) 73.79

Q12. 81% of 2300 -? = 34% of 596
(a) 1751.36
(b) 1680.36
(c) 1791.36
(d) 1660.36
(e) 1691.36

Q13. (7921 ÷ 178) – 5.5 = √(?)
(a) 39
(b) 1369
(c) 1521
(d) 1225
(e) 1444






Solutions 



















Daily Dosage - -JRF / SRF / IBPS Agricultural Field Officer Study Material -Important Laws / Acts / Regulations -Related to Agriculture

Important Laws / Acts / Regulations -Related to Agriculture 


  • Prevention of Food Adulteration Act 1954
  • Plant Quarantine (Regulation of Import into India) Order, 2003
  • Meat Food Product Order 1973 
  • Milk And Milk Product Order 1992
  • Bureau Of Indian Standards Act, 1986
  • Standards On Weight And Measurement Act, 1976 
  • Livestock Importation Act, 1898
  • AGMARK Act ,1937
  • The Infant Milk Substitutes, Feeding Bottles and Infant Foods Act ,1992
  • Export (Quality Control and Inspection) Act, 1963 
  • Essential commodities Act,1955 
  • Indian Explosives Act,1884
  • Energy Conservation Act, 2001A. Food Laws The main Acts/Regulations/Control orders to regulate trade
  • Prevention of Food Adulteration Act 1954 
  • Plant Quarantine (Regulation of Import into India) Order, 2003
  • Meat Food Product Order 1973
  • Milk And Milk Product Order 1992 
  • Bureau Of Indian Standards Act, 1986
  • Standards On Weight And Measurement Act, 1976
  • Livestock Importation Act, 1898 
  • AGMARK Act ,1937
  • The Infant Milk Substitutes, Feeding Bottles and Infant Foods Act ,1992
  • Export (Quality Control and Inspection) Act, 1963 
  • Essential commodities Act,1955 
  • Indian Explosives Act,1884
  • Energy Conservation Act, 2001

Daily Dosage -General Agriculture- Important Onemarks For All Competitive Exams

General Agriculture Important Onemark

  • Which herbicide used in cotton :- Diuron 
  • Yellow mosaic variety of moong is :- Pant moong -4
  • Taungya cultivation started for the 1st time in :- Burma
  • Pink boll worm of cotton belongs to family :- Gelechiidae 
  • Supplementary pollination is recommended in :- Sunflower 
  •  Guttation occurs in plant through :- Stomata & Hydathode
  • Cultivation of crops in surface soil is known as :- Geocropping 
  • TPS variety of potato :- HPS-1/113
  •  Movement of P & K from soil to the root surface take place due to :- Mass flow 
  • ROM - is a variety of :- Mothbean
  • Geographical area of India is?  328 Mha   
  • Redness in Apple is due to? Anthocyanin                                                                        
  • Yellow coloured fruits and vegetables are rich source of? VitamiA                           
  • Yellow colour of cow milk is due to the presence of? Carotene  
  • Edible portion of a mango fruit is its? Mesocarp  
  • Kesar (saffron) belong to the family of? Iridiceae
  • Specific gravity of milk is? 1.028- 1.032                         
  • Developed bitterness of groundnut kernel is mainly due to? Aflatoxin  
  • The paddy variety which is also known as Miracle rice of India is? Jaya   
  • Kisan call centre begun in the year? 2004     
  • Hormone used as an herbicide?  2, 4-D (>20 PPM)  
  • Root promoting hormones? IBA
  • Flower setting hormone? NAA                                     
  • The cutting of weed to the ground level is known as? Mowing 
  • NABARD came into existence on? 12 July, 1982   
  • The scientific name of Arhar is? Cajanus cajan 
  • T.S.S. of papaya jam is? 68.5%                                                     
  • The term ‘horticulture’ is derived from which of the following language? Latin  
  • The development of more than one embryo in the seed is known as? Polyembryony 
  • The botanical name of Okra is? Abelmoschus esculentus       
  • The common name of Cyprus rotundus is? Nut grass    
  • The scientific/botanical name of soybean is? Glycine max  
  • The square method of planting is used in? Mango     
  • The weeds which complete their life cycle in two years are known as? Biennial weeds


Daily Dosage - -JRF / SRF / IBPS Agricultural Field Officer Study Material - Pea Onemark

  Pea Oneliner - Agronomy Important Q & A For All Competitive Exam

1.    Origin of pea: Mediterranean region of Europe & West Asia

2.    Botanical name of pea: pisum sativum

3.    Family of pea: leguminaceae/papilonaceae

4.    Chromosome number of pea: 2n=14

5.    Germination type of pea: hypogeal

6.    Other name of pea: pea, matar (Hindi)

7.    Inflorescence of pea: axillary raceme

8.    Annual herbaceous well developed tap root system plant

9.    Maturity of pea is measured by Tendrometer

10.    Seed multiplication ratio of pea: 1:19

11.    Seed rate of garden pea: 100-120 kg/ha

12.    Seed rate of field pea: 70-80 kg/ha

13.    Depth of sowing of pea: 5-7 cm

14.    Protein in peaa: 22-23%

15.    Test weight of pea: 100 g

16.    pea is a C3, long day, self pollinated

17.    Water requirement to pea: 300-350 mm

18.    Storage moisture of pea: 10-11%

Blood Relation Study Material

Blood Relation - Study Material


• Blood Relation is a must-do part of the exam. As it may come for 5 marks and you know every mark is important.

• In Blood Relation question certain information is given about the members of the family. Based on that information you need to find out the relationship between a particular member of the family.

• Now, take a look at below given “Generation Table” which will help you to understand the different relationship.

Blood relation For Bank Exam

We are presenting the relation in two different forms:

1. Relations of paternal side:

i. Father’s Father – Grandfather

ii. Father’s Mother – Grandmother

iii. Father’s Brother – Uncle

iv. Father’s Sister – Aunt

v. Children of Uncle – cousin vi. Wife of Uncle – Aunt vii. Children of Aunt – Cousin viii. Husband of Aunt – Uncle

2. Relations of maternal side:

i. Mother’s Father – Maternal Grandfather

ii. Mother’s Mother –Maternal Grandmother

iii. Mother’s Brother – Maternal Uncle

iv. Mother’s Sister – Aunt

v. Children of Maternal Uncle – Cousin

vi. Wife of Maternal uncle – Maternal Aunt

• The solve questions of Blood Relations easily, you can take help of “Generation Tree”.

 Types of questions asked from Blood Relations: 

1. Based on Dialogue or Conversation

2. Based on Puzzles

3. Based on Symbolically coded

Based on Conversation or Dialogue-

In this type of questions, the one person talking to or doing chit-chat with other person giving information by pointing to some picture or person.

Example: Pointing to a lady on the stage, Monika said, “She is the sister of the son of the wife of my husband.” How is the lady related to Monika?

Solution: Find who you can easily relate to and be that person-then go about creating one relation after another.

In this question, be Monika-then start from the end of the sentence.

“My husband” = Monika’s husband

‘Wife of my husband’ = is me = Monika

‘Son of the wife of my husband’ = My Son

‘Sister of the Son of the wife of my Husband’ = My Son’s Sister = My daughter

‘She’ is the sister of the son of the wife of my husband’ = the lady on the stage = the lady being pointed out = my daughter.

So, the lady on the stage is Monika’s daughter.

Based on Puzzles: 

In this type of question, you have to conclude the relations between two given person based on more than one information given in the question.

Example: In a family of eight people, there is three generations and two couples. R is the brother of Z, who is the grandchild of X. X is married to P. L is the father of Z. P is the father in law of U.  L is the brother of Y and K. K is the aunt of Z. How is P related to K?

(a) Grandfather

(b) father in law

(c) Father

(d) Mother

(e) None of these

So, P is the father of K.

Based on Symbols: 

In this type of question, information is coded in the form of symbols life D, #, $, % ……. etc.

Example: Read the following information carefully.

(i) P % Q means P is the father of Q.

(ii) P @ Q means P is the brother of Q.

(iii) P $ Q means P is the daughter of Q.

(iv) P * Q means P is the son of Q.

(v) P © Q means P is the mother of Q

(vi) P & Q means P is the wife of Q

Who among the following is daughter in law of Z in the relation- ‘T & Y % S & X * Z’ is true?

(a) X

(b) Y

(c) T

(d) S

(e) Can’t be determine

here, from the above generation tree. we can easily find out S is daughter in law of Z.

 


Input-Output for Bank Exam Study Material

 Input-Output for Bank Exam Study Material

Input-Output play an important role in an examination. 5 Questions come from this topic in every bank exam . Using a right approach you can easily score a good marks in this topic.

In input-output problems you are asked to imagine that there is some kind of computer or a word-processing machine and this machine performs some operations on a given input. These operations are performed repeatedly as per a per-fixed pattern or rule and subsequently we have different output in different steps.

These (Input-output) types of questions regularly come in the competitive examinations 
Although they may look complex but they are not so tough only factor in that they are time consuming and time is premium in a competitive test these days.
Guidelines: (Approach for solving the questions)

(1) Our 1st step will be to see the input.
(2) In 2nd step, we should see the final output.
(3) And at last, we should focus on first step and so on to understand the pattern of arrangement.

Types of pattern followed in Input-output:

  • Words are in ascending order     : For example : a, b, c, d, e, f, g, h, i……
  • Words are in descending order   : For example : X, W, S, P, K, H, D…….
  • Number are in ascending order  : For example : 1, 2, 7, 9, 10, 13, 17, 22, ……….
  • Numbers are in descending order : For example : 29, 26, 24, 21, 17, 13, 10, 9, 7, 4,…….
  • Count of words are in ascending order: For example : I, do, pen, wise, Mango, should ……….
  • Count of words are in descending order :For example : Mangoes, could, kite can, so, I,…..
  • Sum of digits in ascending order: For example : 10, 11, 21, 13, 32, 51, 61, 81, 28……..
  • Sum of digits in descending order :For example : 28, 81, 61, 51, 32, 13, 21, 11, 10……

Points to Remember
(1) In Input-output, the most important thing is to understand the pattern of the steps, how they are arranging.
(2) Looking at the last and other steps, you can understand the pattern of question.
(3) Be careful in mix shifting pattern, i.e. shifting from both left and right side.
(4) Some times characters/digits get automatically arranged in steps. So, for that step another
increasing/decreasing characters/digits should be arranged.
(5) The most important thing is to be noted that from given step, previous step can’t be determined.

Example 1- Input: 2568 7625 9732 8214 1129 4622
Step I: 8652 7652 9732 8421 9211 6422
Step II: 6422 7652 8421 8652 9211 9732
Step III: 62 72 81 82 91 92
Step IV: 4 5 7 6 8 7
Explanation: Logic- For step I- All the digits of the given numbers are arranged in descending order within the numbers.
For Step II- All the numbers obtained in step I are arranged in ascending order from the left end.
For Step III- middle two digits of the numbers are omitted.
For step IV- The digits of the numbers obtained in step III are subtracted.

Example 2- Input: phase 73 iconic 24 record 15 under 39 summer 54 36 across
Step I: 24 phase iconic record 15 under 39 summer 54 36 across 73
Step II: phase 24 iconic record 15 39 summer 54 36 across 73 under
Step III: 36 phase 24 iconic record 15 summer 54 across 73 under 39
Step IV: record 36 phase 24 15 summer 54 across 73 under 39 iconic
Step V: 54 record 36 phase 24 summer across 73 under 39 iconic 15
Step VI: summer 54 record 36 phase 24 73 under 39 iconic 15 across
Exaplanation: Logic- (i) The words and numbers are arranged in alternatively in every step starting from the numbers. Two words/number are arranged in each step.
(ii) Even numbers are arranged at the leftmost end in increasing order, while the odd numbers are arranged at the rightmost end in decreasing order in each alternate step.
(iii) The words starting with a consonant are arranged at the left most end in increasing alphabetical order and the words starting with a vowel are arranged at the rightmost end in decreasing alphabetical order in each step.

Example 3- Input: 53 86 22 15 48 93 37 74
Step I: 22 53 86 15 48 93 37 74
Step II: 93 22 53 86 15 48 37 74
Step III: 48 93 22 53 86 15 37 74
Step IV: 53 48 93 22 86 15 37 74
Step V: 74 53 48 93 22 86 15 37
Step VI: 37 74 53 48 93 22 86 15
Step VII: 86 37 74 53 48 93 22 15
Step VIII: 15 86 37 74 53 48 93 22
Explaination: Logic- One even and one odd number are arranged in each alternate step.
Even numbers are arranged at the leftmost end in increasing order, while the odd numbers are arranged at the leftmost end in decreasing order in each alternate step.